# Data structure | oop | assignment | c代写 | c语言代写 – assignment 9 – Graphs

#### assignment 9 – Graphs

Data structure | oop | assignment | c代写 | c语言代写 – 这是一个关于Data structure的题目, 主要考察了关于Data structure的内容,是一个比较经典的题目, 包括了Data structure/oop等方面, 该题目是值得借鉴的assignment代写的题目

#### assignment 9 – Graphs

###### OBJECTIVES

**1. Build an undirected weighted graph

1. Perform Breadth First Traversal (BFT) and Depth First Traversal (DFT)**
###### Overview

You were just a humble map programmer, but that was before the zombies attacked! Now, your skills are put to coordinating the survivors and finding routes between cities that havent been overtaken. Some of the roads between these cities have been overrun and you will have to avoid them, which has caused the nation to be divided into multiple smaller districts (think disconnected components in a graph). You will have to build a graph with each vertex representing a city and each edge between vertices representing a route between them. The

####### following structs will facilitate your graph.

``````/* structure for edge connecting an adjacent vertex */
struct   Edge
{
vertex  *v;
int  distance;
};
/* structure for each vertex in the graph */
struct  vertex
{
std::string  name;
bool  visited;
std::vector  <  Edge  > Edges;  // stores edges to adjacent vertices
};
``````

####### You will store the graph as a vector of vertex structs, where each city contains an adjacency list

####### stored as a vector of Edge structs. This Data structure is described in Graph.hpp and can be

represented like this:

``````Which would represent the following graph:
``````
###### Graph Class

There is no need to manage dynamic memory in this assignment so you may leave your constructor/destructor empty. void addVertex(std::string cityName ) Create a new vertex with name cityName and push it back to your vector of vertices. void addEdge(std::string city1 , std::string city2 , int distance )

####### Establish a single edge from city1 to city2 . Create an edge with distance equal to

distance and v equal to the address of the vertex with name city2 . Then push back the edge to the Edges vector of the vertex with name city1 . void displayEdges() For each vertex in your vertices vector, print the city name and each city with which it is connected along with the distance in miles between them using the following example format. The graph below has three vertices that are all connected. // Boulder has an edge to Denver with distance 2 and an // edge to Chicago with distance 15 Boulder–>Denver (2 miles)Chicago (15 miles) Chicago–>Boulder (15 miles)Denver (10 miles) Denver–>Boulder (2 miles)***Chicago (10 miles) void printDFT() Use a depth first traversal of the graph to print the names of every city beginning with the first vertex in your vertices vector. Use your helper functions setAllVerticesUnvisited and DFT_traversal . Note that there may be disconnected components in the graph! void printBFT() Same as above with a breadth first traversal instead. void setAllVerticesUnvisited() L oop through your vertices vector and set each vertexs visited field to false. This function should be called right before any traversal (BFT, DFT) that uses the visited member. *vertex findVertex(std::string name ) Return a pointer to the vertex with the specified name . **void BFT_traversal(vertex *** v ) Perform a breadth first traversal of the graph beginning with vertex v , printing the name of each vertex you visit. cout << v->name << endl **; void DFT_traversal(vertex *** v ) Same as above with depth first traversal instead.

###### Driver

Unlike previous assignments, your program will not have a menu. Instead, it should begin by reading data out of a file, where the name of this file is passed as a command line argument .

####### An example file can be found on Moodle with the name simpleCities.txt . This file is in the

following format cities,Boulder,Denver,Chicago,Boston,Austin Boulder,0,2,15,-1,- Denver,2,0,10,-1, Chicago,15,10,0,5,- Boston,-1,-1,5,0,- Austin,-1,8,-1,-1, The first row and first column contain the name of each city in the graph. The rest of the values correspond to the distance between those cities A positive value represents the distance(in miles) between the row and the column city While the value -1 indicates that there is no path connecting the two cities. Every time you read in a new edge with a distance greater than 0, use the following print statement: cout << ” … Reading in “ << city << ” — “ << connectedCity << ” — “ << distance << endl ; After your graph is built, demonstrate your different traversal methods with the following lines of code: cout << “—————————— ” << endl << “Breadth First Traversal” << endl << “——————————” << endl ; g.printBFT(); cout << “—————————— ” << endl << “Depth First Traversal” << endl << “——————————“<< endl ; g.printDFT(); cout << “—————————— ” << endl << “Display Edges” << endl << “——————————“<< endl ;

g.displayEdges();